Physics: Asurveillance satellite has a camera which detects 550 nm light and is equipped with a 35 cm diameter lens. if the satellite is at an altitude of 160 km, what is the minimum spacing between two objects on the ground that the camera can barely resolve (in m)?

Given, We know that, Which contains variable,So, is not constant....

Asurveillance satellite has a camera which detects

Adeenieweenie

02.01.2022

0.3067 m

Explanation:

Resolving power of a lens is given by the expression

R.P = 1.22λ / D

where λ is wavelength of light used, D is diameter of the lens

Substituting the data given

R.P in radian =

$\frac{1.22\times550\times10^{-9}}{35\times10^{-2}}$

R P = 19.17 X 10⁻⁷ radian

If d be the minimum spacing between two objects on the ground that is resolvable by lens

$\frac{d}{160\times10^3} =19.17\times10^{-7}$

d = 0.3067 m

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royaltyy6533

08.07.2020

Given,

$\frac{d v}{d t}=600$ cubic centimeters/min.$

We know that,

$V=\frac{4}{3} \pi r^{3}$

$\frac{d v}{d t}=4 \pi r^{2} \frac{d r}{d t}\\\Rightarrow \quad 600=4 \pi \gamma^{2} \frac{d \gamma}{d t}\\$

$\frac{dr}{dt}=\frac{150}{\pi r^{2} }$

Which contains variable,

So, $\frac{dr}{dt}$ is not constant.

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