Physics: At the base of a hill, a 90 kg cart drives at 13 m/s toward it then lifts off the accelerator pedal). If the cart just barely makes it to the top of this hill and stops, how high must the hill be?

At the base of a hill, a 90 kg cart drives at 13

aalichia

21.04.2021

the height of the hill is 8.622 m.

Explanation:

Given;

mass of the cart, m = 90 kg

speed of the cart at the base, v = 13 m/s

Let the height of the hill = h

Apply the principle of conservation of energy, to determine the height of the hill.

¹/₂mv² = mgh

¹/₂v² = gh

$h= \frac{1}{2} \times \frac{v^2}{g} \\\\h = \frac{1}{2} \times \frac{13^2}{9.8} \\\\h = 8.622 \ m$

Therefore, the height of the hill is 8.622 m.

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