Atruck accelerates from a stop to 27m/sec in 9 minutes. what was the trucks acceleration?
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Ответ:
Vf = 27 m/s
t = 9 min = 540 s
1 min = 60 s
9 min = 540 s
a = ? m/s^2.
vf = vi + at
27 = 0 + 540a
27 = 540a
27/540 = 540a/540
27/540 = a
0.05 = a.
The truck's acceleration was 0.05 m/s^2.
Ответ:
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