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krystalhurst97
27.06.2019 •
Physics
Awoman walks 237 m in the direction 27.2 east of north, then 335 m directly east. find the difference between the distance the woman walks and the magnitude of her displacement. (answer in m.)
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Ответ:
81.1 m
Explanation:
X = 237 m 27.2 east of north 237 (Sin27.2 i + Cos 27.2 j)
X = 108.33 i + 210.8 j
Y = 335 east = 335 i
Displacement = X + Y = 108.33 i + 210.8 j + 335 i = 443.33 i + 210.8 j
(magnitude of displacement)^2 = 443.33^2 + 210.8^2
magnitude of displacement = 490.9 m
Distance traveled = 237 + 335 = 572 m
Difference in the magnitude of displacement and distance = 572 - 490.9
= 81.1 m
Ответ:
the first law of thermodynamics.
Explanation: