Before colliding, the momentum of Block A is -100 kgm/s, and Block B is -150 kgm/s. After, Block A has a momentum -200 kgm/s. What is the momentum of Block B afterwards? (Unit = kgm/s)
Remember: right is +, left is -

Before colliding, the momentum of Block A is -100 kg*m/s, and Block B is -150 kg*m/s. After, Block

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Ответ:

lizzy2951

25.09.2020

Physics

$7,500\:\text{Watts}$

Explanation:

Power is given by $P=\frac{W}{\Delta t}$ , where is work and $\Delta t$ is elapsed time. To calculated work, we'll use $W=F\Delta x$ , where is force and $\Delta x$ is displacement. Substituting given values, we have:

$W=10\cdot 50\cdot 60=30,000\:\text{J}$ .

Now plugging this in to our power equation, we get:

$P=\frac{30,000}{4}=\boxed{7,500\:\text{W}}$

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Before colliding, the momentum of Block A is -100 kg*m/s, and Block B is -150 kg*m/s. After, Block A has a momentum -200 kg*m/s. What is the momentum of Block B afterwards? (Unit = kg*m/s) Remember: right is +, left is -