Calculate the energy (in MeV) released in the decay of 239Pu. (Assume 1 u = 931.5 MeV/c2.) MeV (b) What fraction of the mass of a single 239Pu is destroyed in the decay? The mass of 235U is 235.043924 u.

m

Explanation:

75.8 %

Explanation:

Half-life of tritium= 12.33 years

First we have to calculate the rate constant, we use the formula :

Now we have to calculate the age of the sample:

Expression for rate law for first order kinetics is given by:

where,

k = rate constant  =

t = age of sample  = 5 years

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process  = a g

Now put all the given values in above equation, we get

Thus 75.8 percentage of a sample will remain after 5 years have passed.