Can someone please help me with this problem?

26.6m/s is the answer for this question

Both will hit the ground at the same time because their initial vertical velocity is the same and they are accelerating downward at the same rate (-9.8 m/s^s). Ball A will travel further because it has a greater horizontal velocity and both balls have a horizontal acceleration of 0. Their horizontal velocity will remain contestant and they will travel for the same amount of time. The if t is constant and the v of ball A is greater then D will be greater in the equation
D (distance) = vt+1/2•a•t^2