Physics: Coherent monochromatic light falls perpendicularly on two slits (each of width 0.10 mm) separated by 0.50 mm. In the resulting interference pattern on a screen 2.80 m away, adjacent bright fringes are separated by 2.80 mm. (a)What is the wavelength of the light that falls on the slits

Coherent monochromatic light falls perpendicularly - id13600236, caitlinmariesmith05

hoosierkid5633

02.07.2021

The correct answer is " $0.5\times 10^{-6} \ m$ ".

Explanation:

Given:

$\frac{\lambda D}{d} =2.8\times 10^{-3}$

$d = 0.5\times 10^{-3}$

D = 2.80

Now,

The wavelength will be:

⇒ $\lambda = 2.8\times 10^{-3}\times \frac{d}{D}$

By putting the values, we get

⇒ $=\frac{2.8\times 10^{-3}\times 0.5\times 10^{-3}}{2.8}$

⇒ $=\frac{1.4\times 10^{-6}}{2.8}$

⇒ $=0.5\times 10^{-6} \ m$

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sanic123

05.02.2023

Do you have a picture of the models?

Explanation:

I can not answer if there is no pictures

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