manasangreddy2921
05.08.2019 •
Physics
Determine the minimum amount of energy (in mev) needed to remove a neutron from a 88sr nucleus. (for all masses, keep six places beyond the decimal point when performing your calculations. then round your final answer to at least three significant figures.)
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Ответ:
11.106 Mev.
Explanation:
Sr⁸⁸ → Sr ⁸⁷ + ₀n¹
87.905612 86.908877 1.008664 ( atomic masses in amu )
mass defect = ( 86.908877 + 1.008664) - 87.905612 = .011929 amu.
Equivalent energy in MeV = .011929 x 931 = 11.106 MeV
Ответ:
from where to where should we answer to