Physics: Estimate the volume of a typical home (2420 ft^2 in size and 10 ft tall) Answer in units of m^3

Explanation:As we know that the equation of particle position is given asNow the speed of the particle is given asnow we know that potential energy and kinetic energy is equalso we haveso we will have...

Estimate the volume of a typical home (2420 ft^2 - id2420210612341, bravooyessenia

Ответ:

normarismendoza

17.03.2022

Physics

volume = 683.53 $m^{3}$

Explanation:

From the given question,

area = 2420 $ft^{2}$

height = 10 ft = 3.048 m

But,

1 $ft^{2}$ = 0.092903 $m^{2}$

So that,

2420 $ft^{2}$ = 224.8254 $m^{2}$

Volume = area x distance

= 224.8254 x 3.048

= 683.5262

volume = 683.53 $m^{3}$

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Ответ:

myth28

13.09.2022

Physics

$t = \frac{5}{12} s$

Explanation:

As we know that the equation of particle position is given as

$x = A cos(\omega t + \phi_0)$

Now the speed of the particle is given as

$v = A\omega sin(\omega t + \phi_0)$

now we know that potential energy and kinetic energy is equal

so we have

$\frac{1}{2} mv^2 = \frac{1}{2}kx^2$

so we will have

$A^2\omega^2 sin^2(\omega t + \phi_0) = A^2\omega^2 cos^2(\omega t + \phi_0)$

$tan^2(\omega t + \phi_0) = 1$

$\omega t + \phi_0 = \frac{\pi}{4} or \frac{3\pi}{4}$

$\pi t = \frac{3\pi}{4} - \frac{\pi}{3}$

$\pi t = \frac{5\pi}{12}$

$t = \frac{5}{12} s$

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Estimate the volume of a typical home (2420 ft^2 in size and 10 ft tall) Answer in units of m^3

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