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ethangeibel007
21.06.2020 •
Physics
f the CD rotates clockwise at 500 rpmrpm (revolutions per minute) while the last song is playing, and then spins down to zero angular speed in 2.60 ss with constant angular acceleration, what is ααalpha, the magnitude of the angular acceleration of the CD, as it spins to a stop?
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Ответ:
The magnitude of the angular acceleration is![a = 20.14 rad/s^2](/tpl/images/0691/1980/768d1.png)
Explanation:
From the question we are told that
The angular speed of CD is![w_{CD} = 500 rpm = \frac{500 rpm}{\frac{60 \ s }{1 \ min} } * \frac{2 \pi }{ 1 \ rev} = 52.37 rad/s](/tpl/images/0691/1980/8d44e.png)
time taken to decelerate is![t_{CD} = 2.60\ s](/tpl/images/0691/1980/9fd66.png)
The final angular speed is![w_f= 0 \ rad/s](/tpl/images/0691/1980/640ae.png)
The angular acceleration is mathematically represented as
substituting values
The negative sign show that the CD is decelerating but the magnitude is
Ответ:
yes she could she can do one peace of her iron and she can do the rest of it tomorrow