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JayceMeyers06
14.07.2020 •
Physics
Find the buoyant force on a brass block 10.5 cm long by 12.3 cm wide by 15.0 cm high when placed in (a) water, (b) glycerine, and (c) mercury
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Ответ:
(a) F = 18.99 N
(b) F = 23.96 N
(c) F = 258.56 N
Explanation:
First we need to find the volume of the block:
Volume of Block = V = (Length)(Width)(Height)
V = (10.5 cm)(12.3 cm)(15 cm)
V = (0.105 m)(0.123 m)(0.15 m)
V = 0.00194 m³
Now, the buoyant force i given by the formula:
F = (Density of Fluid)(V)(g)
(a)
F = (Density of Water)(V)(g)
F = (1000 kg/m³)(0.00194 m³)(9.8 m/s²)
F = 18.99 N
(b)
F = (Density of Glycerine)(V)(g)
F = (1260 kg/m³)(0.00194 m³)(9.8 m/s²)
F = 23.96 N
(c)
F = (Density of Mercury)(V)(g)
F = (13600 kg/m³)(0.00194 m³)(9.8 m/s²)
F = 258.56 N
Ответ:
Renaissance
Explanation:
:)