For the crystal violet hydroxylaton reaction, here are the numerical values for the x, y, and z labels on the y-axis to the right.
x = 517.21 kj/mol
y = 478.22 kj/mol
z =125.34 kj/mol
using the values calculated for x, y, and z, calculate ea and ? g for this reaction.

ε = 12.9257 V

Explanation:

To do this we need to see what is happening in both cases, when the lights are not being used and when the lights are used.

We will call case 1, the part when the lights are not being used, and case 2 when they're used.

Case 1:

Here, we should write the expression that will help us to determine the emf of the battery, which is:

ε - I₁R = V₁   (1)

Where:

ε: Emf of the battery

I: current of the car

R: Resistance

V: Voltage

Applying this expression with the given data, we have the following:

ε - 54R = 9.63    (2)

For the moment, we can't do anything because we have two incognites. Let's see what happen when we write the expression for case 2.

Case 2:

Applying the same as case 1 but using the other data we have:

ε - I₂R = V₂

Replacing we have:

ε - 2.06R = 12.8    (3)

Now, we can use (2) and (3) and solve for ε calculating the resistance:

ε = 12.8 + 2.06R   (4)

ε = 9.63 + 54R     (5)

Equalling both:

12.8 + 2.06R = 9.63 + 54R

12.8 - 9.63 = 54R - 2.06R

3.17 = 51.94R

R = 3.17 / 51.94 = 0.061 Ω

With this value, we can calculate the emf, using equation (4) or (5):

ε = 12.8 + 2.06(0.061)

Hope this helps