jones03riley
02.11.2019 •
Physics
(from tipler, problem 8-40 on p. 282). a wedge of mass m is placed on a frictionless horizontal surface, and a block of mass m is placed on the wedge, which also has a frictionless surface. the block’s center of mass moves downward a distance h as the block slides from its initial position to the horizontal floor. (a) what are the speeds of the block and of wedge as they separate from each other and go their own ways? (b) check the plausibility of your answer to (a) by considering the limiting case when m is much greater than m.
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Ответ:
Explanation:
The loss of potential energy of the block is converted into kinetic energy of both the block and wedge.
loss of potential energy
= mgh
If v₁ and v₂ be the velocity of block and wedge at the time of separation
applying conservation of energy in horizontal direction ( no force acting in horizontal direction )
m v₁ = M v₂
Applying conservation of mechanical energy
mgh = 1/2 mv₁² + 1/2 M v₂²
1/2 mv₁² + 1/2 M ( mv₁ / M )² = mgh
1/2 mv₁² ( 1 + m/M ) = mgh
v₁² = 2gh / ( 1 + m/M )
v₁ =
v₂ =( m / M) v₁
v₂= m / M
If M is much greater
M+m = M
v₁ =
v₂ =
Ответ:
A. Even, smooth
Explanation:
In regular reflection, light reflected from a smooth surface in a definite direction