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reesewaggoner8
01.06.2021 •
Physics
(give the answer or I'll report) please solve it with the steps
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Ответ:
The required elastic potential energy is 0.068J
Explanation:
Given,
Spring force constant, k= 3.4 N/M
Spring stretch length/ Displacement, x= 0.2m
We know,
Elastic potential energy, V=![\frac{1}{2} kx^{2}](/tpl/images/1357/2160/63641.png)
=![\frac{1}{2}*3.4*(0.2)^{2}](/tpl/images/1357/2160/135e2.png)
=![\frac{0.136}{2}](/tpl/images/1357/2160/10b87.png)
=0.068
∴The required elastic potential energy is 0.068J
Ответ: