jamesgraham577
08.02.2022 •
Physics
Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1)), determine the magnitude and direction of B⃗ −A⃗ .
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Ответ:
Explanation:
Given:
Charge = q
Electric field strength =
weight of the droplet = mg
The charge is suspended motionless. This is because the electric force on the charge is balanced by the weight of the droplet.
electric force on charged droplet,
This is balanced by the weight,
Equating the two: