Good morning help me pls !!!

The force applied to the spring is 35,780 N

Explanation:

Given;

extension of the spring, x = 200 mm = 0.2 m

energy stored in the spring, E = 3578 J

The force applied to the spring is calculated as;

E = ¹/₂Fx

where;

F is the applied force

F = 2E/x

F = ( 2 x 3578) / 0.2

F = 35,780 N

Therefore, the force applied to the spring is 35,780 N