Physics: he gravitational force between two objects of masses m1m1m_1 and m2m2m_2 that are separated by distance rrr is

he gravitational force between two objects of

Ответ:

babiea612

08.02.2022

Physics

$F = \frac{6.67408m_1 m_2}{10^{11}r^2}$

Explanation:

Given

Object_1 = m_1

Object_2 = m_2

Distance = r

Required

Determine the force of attraction

This is calculated as:

$F = \frac{GMm}{d^2}$

Where

M = mass of object 1

m = mass of object 2

d = distance

Where G = gravitational constant

$G = 6.67408 * 10^{-11}\ m^3 kg^{-1} s^{-2}$

Substitute these values in

$F = \frac{GMm}{d^2}$

$F = \frac{6.67408 * 10^{-11} * m_1 * m_2}{r^2}$

$F = \frac{6.67408 * m_1 * m_2* 10^{-11}}{r^2}$

$F = \frac{6.67408m_1 m_2* 10^{-11}}{r^2}$

$F = \frac{6.67408m_1 m_2}{10^{11}*r^2}$

$F = \frac{6.67408m_1 m_2}{10^{11}r^2}$

0,0(0 оценок)

Ответ:

loraine4664

05.05.2022

Physics

1. Transmission Control Protocol / Internet Protocol

2. In the seven-layer OSI model of computer networking, the network layer is layer 3. The network layer is responsible for packet forwarding including routing through intermediate routers.

3. Network Access Control is an approach to computer security that attempts to unify endpoint security technology, user or system authentication and network security enforcement.

0,0(0 оценок)

he gravitational force between two objects of masses m1m1m_1 and m2m2m_2 that are separated by distance rrr is

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Physics

Ask an AI advisor a question