Physics: Horizontally-polarized light passes through a polarizing sheet, and only 15 % of the intensity of the incident light is transmitted through the sheet. what angle does the polarization of the light make with the horizontal after passing through the polarizer?

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Horizontally-polarized light passes through a polarizing

IDespretlyneedhelp

10.01.2022

To develop this problem it is necessary to apply the concepts related to the law of Malus.

Malus's law defines that,

$I = I_0 cos^2\theta$

Where

I_0 = Intensity of incident light

I = Intensity of polarized light

Therefore according to the information

$I = I_0 \frac{15}{100}$

I = 0.15I_0

Equation we have that

$0.15 I_0 = I_0 \frac{15}{100}$

$cos^2\theta = 0.15$

$cos\theta = 0.3872$

$\theta = cos^{-1}(0.3872)$

$\theta = 67.2\°$

Therefore the angle the polarization of the light make with the horizontal after passing through the polarizer is 67.2°

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