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20.03.2020 •
Physics
How far the first bright diffraction fringe is from the strong central maximum if the screen is 12.0 m away. Express your answer to three significant figures and include the appropriate units.
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Ответ:
λ=wavelength = 620 nm = 620 x 10-9 m
d = slit width = 3.40 x 10-3 mm = 3.40 x 10-3 x 10-3 m = 3.40 x 10-6 m (since 1 mm = 10-3 )
n = order = 1
D = screen distance = 12 m
Using the formula ::
d Sin\theta = (2n + 1) (\lambda/2)
for small angles, Sin\theta = tan\theta = x/D
x = distance of fringe from central maxima
D = distance of screen = 12 m
d (X/D) = (2n + 1) (\lambda/2)
(3.40 x 10-6) (X/12) = (2 + 1) ((620 x 10-9)/2)
X = 3.28 m
Ответ:
Explanation:
The distance of any bright fringe from the central maximum on the screen in a single slit diffraction is given by,
Ym = (2m + 1) lL/2a
where m = 1
l = wave length,
L = width of the slit
a = distance from the centre of the slit
m = 1, l = 640 x 10-9nm , L = 3.4 x 10 -3 and a = 12m.
Ym = (2x1 +1) 640 x 10-9 x 3.4 x 10-3 / 2 x 12
= 2.72 x 10-9m
Ответ: