Physics: How fast, in rpm, would a 5.8 kg, 22-cm-diameter bowling ball have to spin to have an angular momentum of 0.21 kgm2/s

How fast, in rpm, would a 5.8 kg, 22-cm-diameter - id582210047879, guitarislife97p73kzu

Ответ:

lexi1268

14.02.2022

Physics

91 rpm

Explanation:

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Ответ:

brackendillman

14.04.2020

Physics

$\alpha = g \frac{MR-mr}{I}$

Explanation:

Let gravitational constant be g (m/s2). So the gravity acting on the turkey is Mg and the gravity acting on the pumpkin is mg. The difference in torques generated by these 2 gravity forces is

$\Delta T = T - t = MgR - mgr = g(MR - mr)$

This torque difference would generate an angular acceleration on the pully system with moments of inertia I, according to Newton 2nd's law

$\alpha = \frac{\Delta T}{I} = g \frac{MR-mr}{I}$

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How fast, in rpm, would a 5.8 kg, 22-cm-diameter bowling ball have to spin to have an angular momentum of 0.21 kgm2/s

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