How high can a human throw a ball if he can throw it with initial velocity 90 mph. a144.3 m
b 91.82 m
c 82.45 m
d99.82 m
e45.52 m

c 82.45 m

Explanation:

To solve this problem, we have to apply the right motion equation.

 Given parameter;

 Initial velocity  = 90mph

 So;

 Using;

      V²  = U² - 2gh ; we can solve this problem

 V is the final velocity = 0mph

U is the initial velocity

g is the acceleration due to gravity

h is the height

 Now insert the parameters and solve;

        We need to convert from mph to m/s

          1 mph  = 0.45m/s

          90mph  = 40.5m/s

    0² = 40.5² - (2 x 9.8 x h)

      0 = 1640.25  - 19.6h

    -1640.25 = -19.6h

           h  = 83.7m