How many electrons pass through a standard 60 watt light bulb in one second?
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Ответ:
W = Energy/time
60 W = x J/1 s
x = 60 J = 60 C·V
(60 C·V)*(1/130 V)*(1 mole e/96,500 C)*(6.022×10²³ electrons/mole electron)
= 2.88×10¹⁸ electrons
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