How much work does gravity do on the compressor during this displacement?

W = mg × (r₂ - r₁)

Explanation:

Work done is the product of force acting and the displacement. In this case, we have to find the work done by the gravity on the compressor during displacement.

Let r₁ and r₂ are the initial and the final position of the body. So, displacement will be, r₂ - r₁.

Work done, W = F × d

Since, F = mg

W = mg × (r₂ - r₁)

Hence, the work done by the gravity on the compressor is " mg × (r₂ - r₁) Joules".

Explanation and Examples

let the mass of the compressor be

mass (m):

height in x axis is (h1)

height in y axis be (h2):

Height difference: h2-h1

displacement x force:

mass x gravity x height

(m)*9.8*(height difference) = ___ J

Since gravity is forcing down, it would be negative!

Put the values that you require and get the answer.

a wave vibrating at right angles to the direction of its propagation.

Explanation: