If a 167 kg object falls from a height of 550 meters, what is the acceleration of that object? (Assume that the initial velocity is 1 m/s and we use G (9.8m/s^2))
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Ответ:
Explanation:
I used 2 different equations to solve this. First,
Δx = v₀t + at² which says that the displacement of an object is equal to its initial velocity times the time in seconds plus one-half the acceleration of the object times the time squared. I solved this for t then plugged into
Let me first say that I used 1.0 as the velocity in the first equation since 1 is too insignificant. Filling into the first equation and using the fact that the object lands 550 meters below the point at which it starts (making the displacement negative):
which simplifies a bit to
and then get everything on one side and factor:
gives us that
t = 10.7 seconds which should be rounded to 11 seconds. I'm going to use t = 11 here.
so
a = -.091 m/s/s
Ответ:
The sun's corona can be seen during a solar eclipse.