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merrickrittany
26.01.2020 •
Physics
If the kinetic energy possessed by a man of 50kg is 625j , the speed of man is
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Ответ:
v= 5 m/s
Explanation: Solution:
KE= 1/2 mv²
Derive to find v.
v = √ 2KE / m
Substitute the values
v = √2x 625 J / 50 kg
= √ 1250 J / 50 kg
= √ 25 kg. m/s /kg
= 5 m/s
Unit for J can be expressed in kg.m/s so we cancel kg and the remaining unit is m/s.
Ответ:
Whats Orisha then I will Give ya the n sir
Explanation: