If the satellite is travelling in the same direction as the earth, what is the interval between successive times at which it will appear vertically ahead to an observer at a
fixed point on the equator?
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0.6m/s²

Explanation:

Given parameters:

Initial velocity  = 3m/s

Final velocity  = 4.5m/s

Time taken  = 2.4s

Unknown:

Average acceleration  = ?

Solution:

To solve this problem, we use the expression:

 Acceleration  =  

v is the final velocity

u is the initial velocity

t is the time taken

    Acceleration  =   = 0.6m/s²