oldless504
16.07.2019 •
Physics
Imagine a carnot engine has a hot reservoir of 680 k and a cold reservoir of 220 k. what is the efficiency of the engine? 58.3% 75.9% 62.3% 72.1% 67.6%
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Ответ:
n = efficiency
QC = Cold Reservoir = 220 K
QH = Hot Reservoir = 680 K
The engine's efficiency is 67.6% .
Ответ:
the other person's right, it's E. 67.6% for plato users :)
Ответ:
This question is in complete, the missing table is uploaded along this answer.
the maximum possible kinetic energy K of the electrons emitted from this new surface is 4.9 eV
Explanation:
Given the data in the question;
copper K = 2.7 eV
If the copper is replaced with a piece of sodium ( Na )
the maximum possible kinetic energy K of the electrons emitted from this new surface = ?
we know that;
Kinetic energy of emitted electrons can be written as;
K = hv - hv₀
where v is frequency, h is Plank's constant, and hv₀ is work function of metal
so lets make hv the subject of formula;
hv = K + hv₀
from the table below, work function of copper is 4.5 eV
so we substitute
hv = 2.7 eV + 4.5 eV
hv = 7.2 eV
Now, If the copper is replaced with a piece of sodium ( Na )
we have;
K = hv - hv₀
from the table below, work function of Sodium is 2.3 eV
so we substitute
K = 7.2 eV - 2.3 eV
K = 4.9 eV
Therefore, the maximum possible kinetic energy K of the electrons emitted from this new surface is 4.9 eV