In 1898, the world land speed record was set by Gaston Chasseloup-Laubat driving a car named Jeantaud. His speed was 39.24 mph (63.15 km/h), much lower than the limit on our interstate highways today. Repeat the calculations of Example 2.7 (assume the car accelerates for 6 miles to get up to speed, is then timed for a one-mile distance, and accelerates for another 6 miles to come to a stop) for the Jeantaud car. (Assume the car moves in the +x direction.) Find the acceleration for the first 6 miles.

the acceleration

Explanation:

Given that:

the initial speed v₁ = 0 m/s i.e starting from rest ; since the car accelerates at a distance Δx = 6 miles in order to teach that final speed v₂ of 63.15 km/h.

So;  the acceleration for the first 6 miles can be calculated by using the formula:

v₂² = v₁² + 2a (Δx)

Making acceleration  a the subject of the formula in the above expression ; we have:

v₂² - v₁² = 2a (Δx)

Thus;

Assume the car moves in the +x direction;

the acceleration

Explanation:

gravitational potential energy = mass x gravitational field strength x height

mass = 60 kg

height = 30 m

let's take the rounded up version of the gravitational field strength = 10 N / kg

so let's just substitute everything in the equation

gravitational potential energy = 60 x 30 x 10

= 18000 J

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