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briarkaltvedt
06.09.2019 •
Physics
In a 100. m race, lisa crosses the finish line after 11.3 s. accelerating uniformly, lisa took 1.85 s to attain maximum speed, which she maintained for the rest of the race. what was lisa's acceleration?
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Ответ:
acceleration = 5.21 m/s²
Explanation:
given data
distance d = 100 m
time v = 11.3 s
max speed time u = 1.85 s
to find out
acceleration a
solution
we know initial speed is zero
and after 1.85 s lisa run 11.3 s
so we consider after 1.85 s lisa run at constant speed that is 11.3 - 1.85 = 9.45 s
we consider lisa run with velocity x
so velocity
V = u +at
x = 0 + a(1.85)
a = x / 1.85 m/s² 1
and distance travel with x = speed × time
distance at x velocity = 9.45 x 2
now calculate the distance to reach at maximum speed by distance formula
distance = ut + 1/2 ×at²
distance = 0 + 1/2 ×(x/1.85)(1.85)²
distance = 0.925 x meters 3
so from equation 2 and 3
total distance = 0.925 x + 9.45 x
100 = 0.925 x + 9.45 x
so x = 9.6385 m/s
so from equation 1
a = x / 1.85 m/s²
a = 9.6385 / 1.85 m/s²
a = 5.21 m/s²
Ответ: