tubakhan4833
03.02.2020 •
Physics
In a laboratory experiment, an ultrasound detector located at d is used to measure the distances of two moving objects, p and q. at a certain moment, p and q are located as shown in the diagram. what is distance pq? . a) 6.82. b)5.66. c)4.74. d)4.24. e)3.89.
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Ответ:
d^2 = (4.24)^2 + (4.24)^2 - 2. (4.24) (4.24) cos 68
d^2 = 2 (4.24)^2 - 2. (4.24) (4.24) cos 68
d = 4.74
so the answer will be letter. C
hope this helps
Ответ:
Side "p" is opposite Angle P
Side "d" is opposite Angle D = 45º + 23º = 68º
Side "q" is opposite Angle Q
Use the Law of Cosines:
d² = p² + q² − 2 • p • q • cos(D)
d² = (4.24)² + (4.24)² − 2 • (4.24) • (4.24) • cos(68º)
d² = 2(4.24)² − 2(4.24)² • cos(68º)
d² = 2(4.24)² • [ 1 – cos(68º) ]
d = 4.74 ft
Ответ:
high tides or low tides
Explanation: