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leannehounschell
14.07.2020 •
Physics
In an experiment to measure the acceleration due to gravity g, two independent equally reliable measurements gave 9.67 m/s2 and 9.88 m/s2. Determine (i) the percent difference of the measurements (ii) the percent error of their mean. [Take the theoretical value of g to be 9.81 m/s2]
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Ответ:
Answer and Explanation:
a. The computation of the percent difference between the measurements is shown below:-
The first value of g is 9.67 and the second value is 9.88
So, difference = 9.88 - 9.67
= 0.21
Percentage difference in measurement is
= +/-2.13
Percent difference with 9.88
Difference = 9.88 - 9.81
= 0.07
= +/-0.71%
b. The Computation of percent error of their mean is shown below:-
Mean of two values is
=![\frac{9.67 + 9.88}{2}](/tpl/images/0705/3411/19adb.png)
= 9.775
Difference = 9.81 - 9.775
= 0.035
Percentage difference is
= +/- 0.36%
Ответ:
Step-by-step explanation:
To be congruent two triangles must be the same shape and size. However they can share a side, and as long as they are otherwise identical, the triangles are still congruent.