ValerieRubyPena

01.09.2021 •

Physics

In H2 + CI2 -> 2HCI How much total bond energy. in KJ/mol, is in the product of the reaction?

A. 677
B. 854
C. 435
D. 427

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Ответ:

summeredki

22.08.2022

Physics

$W=1432.27\ J$

Explanation:

Given:

mass of the cart, $m=22.2\ kg$ inclination of rope above the horizontal, $\theta=27.5^{\circ}$ displacement of cart, $s= 24\ m$ coefficient of kinetic friction, $\mu_k=0.32$

We find the force acting in the direction of the rope responsible for motion of the cart:

$f=\mu_k.R$ ................................................(1)

Here normal reaction R:

$F.sin\theta+R=m.g$ ........................................(2)

Now since the body is moving with a constant velocity:

∴ Kinetic Frictional force = applied force

f=F

$\mu_k.R=F.cos\theta$

$R=\frac{F.cos\theta}{\mu_k}$ ................................................(3)

Putting the value of R from eq. (3) into eq. (2)

$F.sin\theta+\frac{F.cos\theta}{\mu_k}=m.g$

$F=m.g\div (sin\theta+\frac{cos\theta}{\mu_k})$

$F=22.2\times 9.8\div (sin 27.5+\frac{cos27.5}{0.32})$

$F=67.28\ N$ is the force applied along the rope.

Now the work done by the rope:

$W=F.s\ cos\theta$

$W=67.28\times 24\times cos\ 27.5$

$W=1432.27\ J$

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In H2 + CI2 -> 2HCI How much total bond energy. in KJ/mol, is in the product of the reaction?A. 677B. 854C. 435D. 427​