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zaratayyibah
19.10.2019 •
Physics
In the bohr model of the hydrogen atom, an electron moves in a circular path around a proton. the speed of the electron is approximately 2.20 x 10^6 m/s. find (a) the force acting on the electron as it revolves in a circular orbit of radius 0.530 x 10^-10 m and (b) the centripetal acceleration of the electron.
a) fc = m*v^2/ r
fc = 9.10938188*10^-31 * (2.2*10^6)^2 / (0.53*10^-10)
fc = 8.3188 *10^-8 n
b) ac = fc / m =
8.31876*10^-8 / (9.10938188*10^-31) = 9.1321*10^22 m/s^2
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Ответ:
Explanation:
It is given that,
Radius of the circular orbit,
Speed of the electron,![v=2.2\times 10^6\ m/s](/tpl/images/0333/1787/7e980.png)
Mass of the electron,![m=9.1\times 10^{-31}\ kg](/tpl/images/0333/1787/2c33a.png)
(a) The force acting on the electron is centripetal force. Its formula is given by :
(b) The centripetal acceleration of the electron is given by :
Hence, this is the required solution.
Ответ:
si
Explanation: