In watching the examples of momentum by the student, he later used a 4.1 kg bowling ball to hit the pens about 3.5 seconds after he released the ball. By knowing that a bowling lane is 18.3 meters long you can calculate the momentum that the bowling ball hit the first pen with to be *

Momentum = 21.44 N.s

Explanation:

First we need to find the speed of the ball by using following equation. Assuming the speed of ball to be constant:

where,

v = speed of ball = ?

s = distance covered by ball = 18.3 m

t = time taken = 3.5 s

Therefore,

Now, the momentum of ball will be:

Momentum = 21.44 N.s

r₂ = 4 r

Explanation:

For this exercise let's use Newton's second law with the magnetic force

          F = q v x B

bold letters indicate vectors, the magnitude of this expression is

          F = q v B sin θ  

in this case we assume that the angle is 90º between the speed and the magnetic field.

If we use the rule of the right hand with the positive charge, the thumb in the direction of the speed, the fingers extended in the direction of the magnetic field, the palm points in the direction of the force, which is towards the center of the circle, therefore the force is radial and the acceleration is centripetal

           a = v² / r

let's use Newton's second law

           F = ma

           q v B = m v² / r

           r =

Let's apply this expression to our case.

Proton 1

             r = \frac{qB_1}{mv_1}

Proton 2

             r₂ =

in the exercise indicate some relationships between the two protons

*    v₁ = 2 v₂

    v₂ = v₁ / 2

*   B₂ = 2B₁

we substitute

           r₂ =

           r₂ = 4

           r₂ = 4 r