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jabriskie5668
06.05.2020 •
Physics
Investigate the chemical potential μ upon a change in volume. We will use the fact that
F=U−TS and μ=∂F∂N. We will compute μ(Vf)−μ(Vi)
Take N=20 moles (which is 20 times Avagodro's number of particles), T=300 K, Vi=0.01 m^3,Vf=0.02 m^3
For a gas with an excluded volume: U=32NkT+const S=Nkln(V−bN)+const
If b=9 × 10-29 m^3, compute µ(Vf)- µ(Vi)
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Ответ:
Explanation:
Let's rewrite F in terms of N.
C is a constant value.
We know that the chemical potential μ is the partial derivative of F with respect to N.
We can find now the chemical potential μ(Vf).
k is the Boltzmann constantWe can do the same to find μ(Vi).
Therefore µ(Vf) - µ(Vi) will be:
I hope it helps you!
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