Physics: It is a hot, sunny day. the outdoor temperature is 32°c (90°f), and the water temperature is 21°c (70°f). a scuba diver submerses himself while holding a balloon filled with 1.5 l of air. if the balloon shrinks to a volume of 0.5 l at a depth of 20 m, what is the pressure at this depth? (assume that the outdoor pressure is 1 atm.)

It is a hot, sunny day. the outdoor temperature

Ответ:

theojw

12.03.2022

Physics

initially when balloon is in atmosphere then we have

PV = nRT

initial temperature is T = 32 degree C

Initial pressure P = 1 atm

Initial volume V = 1.5 L

now we have number of moles as

$n = \frac{1*1.5}{R*(32 + 273)}similarly when it is submerged into the waterTemperature will be T = 21 degree CVolume will be 0.5 Lnow for same number of moles[tex]PV = nRT$

$P*0.5 = \frac{1*1.5}{R * 305}* R* (21+273)$

P = 2.89 atm

so pressure at this depth will be 2.89 atm

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