Physics: It takes 15 joules of work to bring 3.0 coulombs of positive charge from infinity to a point. what is the electric potential at this point in an electric field?

It takes 15 joules of work to bring 3.0 coulombs

Ответ:

hdhdenjdxk

15.03.2022

The work done to bring the charge from infinity to point A is equal to the variation of potential energy of the charge:
$W=U(A)-U(\infty )= q V(A)- q V(\infty)$
Using $V(\infty)=0$ as reference, we have:
W= q V(A)

from which we find the potential at point A:
$V(A) = \frac{W}{q}= \frac{15 J}{3.0 C}=5 V$

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Ответ:

Bethany0323

01.02.2023

Physics

Explanation:

Conservation of momentum

Initial momentum is zero

mB(1.8) + mE(-2.6) = 0

mB(1.8) = mE(2.6)

mB/mE = 2.6/1.8

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It takes 15 joules of work to bring 3.0 coulombs of positive charge from infinity to a point. what is the electric potential at this point in an electric field?

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