Jill is pulling a 200. Newton sled through the snow at constant velocity using a horizontal force of 10. Newtons. What is the kinetic coefficient of friction of the sled on the snow?

The kinetic coefficient of friction of the sled on the snow is 0.05

Explanation:

The given parameters are;

The weight of the sled Jill is pulling, W = 200 N

The force with which Jill is pulling the the sled = 10 Newtons

The nature of the speed with which the sled is pulled = Constant speed

Therefore, given that the only opposing force to the pulling of the sled = The force of kinetic friction, we have;

The force with which Jill is pulling the the sled = 10 Newtons = The force of kinetic friction,

The force of kinetic friction = The weight of the sled, W × The kinetic coefficient of friction of the sled on the snow,

= W ×

= /W = 10 N/(200 N) = 0.05

The kinetic coefficient of friction of the sled on the snow = = 0.05.

The acceleration due to gravity on Jupiter is 24.79 m/s²,
compared to 9.8 m/s² on Earth ... a ratio of about 2.53 .

So if a person or object were somehow transported to Jupiter,
he/it would weigh

           (2.53) times (Earth weight)

there.