John walks four kilometers east, two kilometers north as shown in the diagram below. What is John’s displacement 4 km

11 km

2 km north

7 km east

~ 2.02 s

lo siento, lo escribí en inglés, mi español no es tan bueno

Explanation:

i considered the gravitational acceleration g = 9.8 m/s^2

using this equation of liner motion

d = Vo . t + 1/2 g t^2

20 = 0 + 1/2 ( 9.8) t^2 ( Vo = 0 since it was static )

(20 × 2 ) ÷ 9.8 = t^2

so t = squareRoot ( 4.08)

t = 2.02