Physics: Justine is ice-skating at the lloyd center. what is her final velocity if she accelerates at a rate of 2.0 m/s for 3.5 seconds?

Justine is ice-skating at the lloyd center. what

whrjegt4jrnfdvj

13.01.2022

7 m/s

Explanation:

Acceleration, $a=\frac {v-u}{t}$

Where v and u are the final and initial velocities of the Justine respectively, t is the time taken for Justin to attain final velocity.

Making v the subject then

v=at+u

Taking u as zero then

Substituting 3.5 for t, 2 as a then

v=3.5*2=7 m/s

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2020davidhines

09.01.2021

The flea will move high to a height of 0.05 meters.

Explanation:

Given that,

Acceleration of the flea, $a=1000\ m/s^2$

Distance, d = 0.5 mm = 0.0005 m

Let u and v are the initial and final velocity of the flea. Using equation of motion as :

v^2-u^2=2ad

$v^2-u^2=2\times 1000\times 0.0005$

v^2-u^2=1 ..........(1)

Using conservation of energy, we get :

$\dfrac{1}{2}mu^2=\dfrac{1}{2}mv^2+mgh$

$\dfrac{1}{2}u^2=\dfrac{1}{2}v^2+(-g)h$

$\dfrac{1}{2}u^2=\dfrac{1}{2}v^2-gh$

$\dfrac{1}{2g}(u^2-v^2)=-h$

$h=\dfrac{1}{2g}$

$h=\dfrac{1}{2\times 9.8}$

h = 0.05 meters

So, the flea will move high to a height of 0.05 meters. Hence, this is the required solution.

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