lanet R47A is a spherical planet where the gravitational acceleration on the surface is 3.45 m/s2. A satellite orbitsPlanet R47A in a circular orbit of radius 5000 km and period 4.0 hours. What is the radius of Planet R47A

Explanation:

The acceleration due to gravity g is defined as

and solving for R, we find that

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration experienced by the satellite is equal to the gravitational force or

The orbital velocity v is the velocity of the satellite around the planet defined as

where r is the radius of the satellite's orbit in meters and T is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

Solving for M, we get

Putting this expression back into Eqn(1), we get

The final speed of the block is 2.97 m/s

Solution:

As per the question:

mass of the ice block, m = 2 kg

distance, d = 0.750 m

Angle,

Now,

We know that the work done can be given as the change in Kinetic energy of the block:

Since, the bock slides we have velocity in the downward direction only along the slope:

Now, the normal force is perpendicular to the displacement of the block, thus does not contribute to the work done, the only component of force that provides the work done is along the plane in the direction the block slides, thus:

Now, by work energy theorem:

Work done, W = Kinetic energy, KE

Thus