Object a, which has been charged to +13.5 nc, is at the origin. object b, which has been charged to -22.05 nc, is at x=0 and y=1.84 cm. what is the magnitude of the electric force on object a?

7.9 x 10^-3 N attractive in nature

Explanation:

QA = 13.5 nC = 13.5 x 10^-9 C

QB = - 22.05 nC = - 22.05 x 10^-9 C

d = 1.84 cm = 0.0184 m

Let the electric force on object A is F.

By use of Coulomb's law in electrostatics

F = K x QA x QB / d^2

F = (9 x 10^9 x 13.5 x 10^-9 x 22.05 x 10^-9) / (0.0184 x 0.0184)

F = 7.9 x 10^-3 N attractive in nature

Hi!

So I don't know what the heck net force is, but I think the box would move right because there is more force moving to the right.