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BrandonBBB
17.09.2021 •
Physics
Phương trình chuyển động của một chất điểm dọc theo trục Ox có dạng: x = 40 – 10t (m, s).
a. Xác định tọa độ ban đầu, vận tốc và hướng chuyển động. Sau bao lâu thì về tới gốc tọa độ?
b. tính quãng đường đi được sau 2h chuyển động?
Solved
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Ответ:
40 J
Explanation:
Work = change in energy
W = 1/2 k (Δx)²
First we need to find the value of k.
F = kΔx
10 N = k (0.04 m)
k = 250 N/m
Solving for work
W = (250 N/m) (0.40 m)²
W = 40 J