PLEASE HELP ME! A hockey puck travels a displacement of 4.2 m [S38°W]. It is then struck by a hockey player's stick and undergoes a displacement of 2.7 m [E25°N]. What is the puck's total displacement?

2H₂S + SO₂ —> 2H₂O + 3S

Explanation:

From the question given above, the following equation were obtained:

H₂S + SO₂ —> H₂O + S

The equation can be balance as illustrated below:

H₂S + SO₂ —> H₂O + S

There are 2 atoms of O on the left side and 1 atom on the right side it can be balance by writing 2 before H₂O as shown below:

H₂S + SO₂ —> 2H₂O + S

There are 2 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 2 before H₂S as shown below:

2H₂S + SO₂ —> 2H₂O + S

There are 3 atoms of S on the left side and 1 atom on the right side. It can be balance by writing 3 before S as shown below:

2H₂S + SO₂ —> 2H₂O + 3S

Now, the equation is balanced.!