Physics: Please help!Much appreciated!

Please help!Much appreciated! - id7271381, fernandaretanaoxwln0

dozsyerra

31.01.2022

Ts = 3.0×10¯² sec

Explanation:

From the question given:

Ts = 2π √(4.5×10¯² Kg / 2.0×10³ Kg/s²)

The above expression can be evaluated as follow:

Pi (π) = 3.14

Ts = 2π √(4.5×10¯² / 2.0×10³)

Ts = 2 × 3.14 √(4.5×10¯² / 2.0×10³)

Ts = 6.28 × √(2.25×10¯⁵)

Ts = 6.28 × 4.74×10¯³

Ts = 3.0×10¯² sec

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20jacksone

13.11.2020

Acceleration = -1.33ft/s²

Explanation:

Given the following data;

Initial velocity = 3.3ft/s

Final velocity = 3.3ft/s

Time, t = 4s

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Where,

a is acceleration measured in $ms^{-2}$ v and u is final and initial velocity respectively, measured in $ms^{-1}$ t is time measured in seconds.

Substituting into the equation, we have;

$a = \frac{3.3 - 8.3}{4}$

$a = \frac{-5.3}{4}$

Acceleration = -1.33ft/s²

The value is negative because the final velocity is lesser than the initial velocity i.e the student is decelerating.

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