Point charges q1=+2.00μc and q2=−2.00μc are placed at adjacent corners of a square for which the length of each side is 4.50 cm . point a is at the center of the square, and point b is at the empty corner closest to q2. take the electric potential to be zero at a distance far from both charges.part awhat is the electric potential at point a due to q1 and q2? part bwhat is the electric potential at point b? part ca point charge q3 = -4.00 μc moves from point a to point b. how much work is done on q3 by the electric forces exerted by q1 and q2?
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Ответ:
Its velocity is (100m)/(10s)= 10 m/s right.
Explanation:
Since the motion is in a straight line, the displacement is equal to the distance. That makes the magnitude of the velocity equal to the speed.