QUESTION 1 A box, initially at rest, has 33.3 N of force exerted on it for 2.35 s. If the box has a mass of 7.33 kg, what was its velocity at this time?

Velocity of the box: 10.67 m/s

Explanation:

Recall that impulse is defined as the force applied times the time the force is in action. Then we can obtained the value of the impulse given to the box as:

Impulse = F * time = 33.3 N * 2.35 s = 78.225 kg m/s

then we use the momentum of the box at that precise time to find its velocity recalling that :

Momentum = mass * velocity

Then

78.225 kg m/s = 7.33 kg * v

v = 78.225/7.33  m/s = 10.67 m/s

3( -2x + 4)

let's equal the given soln to 0

3(-2x+4) = 0

-6x + 12 = 0

-6x + 12 - 12 = 0-12

-6x = -12

we divide both sides by -6

-6x/-6 = -12/-6

x = 2

Step-by-step explanation:

hope that will help you.