Question 2
a pickle sits 0.08 m from the center of a circular, rotating platter. the platter rotates such that the pickle's
tangential speed is 0.05 m/s. what is the pickle's centripetal acceleration?

Centripetal acceleration, a = 0.03125 m/s²

Explanation:

Given that,

Distance from center of a rotating platter, r = 0.08 m

Tangential speed of the pickle,                v = 0.05 m/s

The centripetal acceleration is given by the formula

                                         a = v²/r

Substituting the given values in the above equation

                                         a =  (0.05 m/s)² / 0.08 m

                                            =  0.03125 m/s²

Hence, the the pickle's centripetal acceleration a = 0.03125 m/s²