Question 2: Sliding block (8 points) A block of mass m is attached to a wall with a spring and is free to slide on a horizontal, frictionless surface. The block is initially pulled a distance x0 from its equilibrium position and is released from rest. (a) [3 points] Question: Determine the position x of the block at which the magnitude of its acceleration is maximal. Justify your answer. (b) [2 points] Question: If the block were pulled a distance 2x0 from its equilibrium position and then released, would the oscillation period T decrease, increase or remain the same

a. X = -Xo

b. Remains same

Explanation:

We can say an Equilibrium Position is a condition in which all acting influences are canceled by others, resulting in a stable, balanced, or unchanging system

Please kindly check attachment for the step by step solution of the given problem.

(a) Kinetic energy of electron after acceleration is 1.602 x 10⁻¹⁹ J

(b) Electric current is 3.0438 x 10⁻⁶ A and its direction is opposite to the direction of electrons.

(c) Charge deposited in 10 s is 3.0438 x 10⁻⁵ C

Explanation:

Given :

Electron charge, q = 1.602 x 10⁻¹⁹ C

Rate of electrons, n = 1.9 x 10¹³ electrons/second

Potential difference, V = 1000 volts

(a)

Kinetic energy of electrons,K = q x V

Substitute the values of q and V in the above equation.

K = 1.602 x 10⁻¹⁹ x 1000 = 1.602 x 10⁻¹⁶ J

(b)

Electric current due to electrons, I = n x q

Substitute the values of n and q in the above equation.

I = 1.9 x 10¹³ x 1.602 x 10⁻¹⁹ = 3.0438 x 10⁻⁶ A

The direction of electric current is opposite to the direction of electrons.

(c)

Time, t = 10 s

Charge deposited, Q = I x t

Substitute the values of I and t in the above equation.

Q = 3.0438 x 10⁻⁶ x 10 = 3.0438 x 10⁻⁵ C